27 gm of saturated solution of nacl at 20 degree celcius when evaporated to dryness leaves a solid reside of 7 gm. calculate solubility of nacl at 20 degree celcius
answer= To calculate the solubility of NaCl at 20 degrees Celsius, we need to first determine the amount of NaCl that dissolved in the 27 grams of saturated solution.
The amount of NaCl dissolved can be found by subtracting the mass of the solid residue (7 grams) from the initial mass of the solution (27 grams):
Amount of NaCl dissolved = Initial mass of solution - Mass of solid residue = 27 grams - 7 grams = 20 grams
Now, to find the solubility of NaCl at 20 degrees Celsius, we divide the amount of NaCl dissolved by the mass of water in the solution.
Assuming the density of water is approximately 1 g/cm³ at 20 degrees Celsius, we can assume the mass of water in the solution is approximately equal to the mass of the solution itself (27 grams).
So, solubility of NaCl = (Amount of NaCl dissolved) / (Mass of water in solution) = 20 grams / 27 grams ≈ 0.741 grams per gram of water
Therefore, the solubility of NaCl at 20 degrees Celsius is approximately 0.741 grams per gram of water.
Submitted by:- sudip jaiswal.
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