Sarina has thrown a cubical dice 2 times. . If 3 is also replaced by 5 in the cubical dice, what is the probability of getting 5 both times?

 

Sarina has thrown a cubical dice 2 times. . If 3 is also replaced by 5 in the cubical dice, what is the probability of getting 5 both times?

If the number 3 on the cubical die is replaced by 5, then there are now two possible outcomes favorable for getting a 5 (the original 5 and the replaced 3). The total number of outcomes for each throw remains 6 on a standard six-sided die. So, the probability of getting a 5 both times is $\frac{2}{6}\times \frac{2}{6}=\frac{1}{9}$.